Home
Class 12
PHYSICS
A capacitor having a capacitance of 20...

A capacitor having a capacitance of 200 `mu F` is charged to a potential difference of 20V. The charging battery is disconnected and the capacitor is connected to another battery of emf 10V with the positive plate of the capacitor joined with the positive terminal of the battery.
(a) Find the charges on the capacitor before and after the reconnection in steady state.
(b) Find the net charge flown through the 10 V battery
Is work done by the battery or is it done on the battery? Find its magnitude.
(d) Find the decrease in electrostatic field energy.
(e) Find the heat developed during the flow of charge after reconnection .

Text Solution

Verified by Experts

The correct Answer is:
(a) `4000mu C, 2000mu C " " (b) 2000mu C " " ` (c) work is done on the battery , 20 mJ
(d) 30 mJ (e) 10 mJ
Promotional Banner

Topper's Solved these Questions

  • CAPACITANCE

    RESONANCE|Exercise Exercise - 3|26 Videos

  • ATOMIC PHYSICS

    RESONANCE|Exercise Advanved level problems|17 Videos

  • COMMUNICATION SYSTEMS

    RESONANCE|Exercise Exercise 3|13 Videos

Similar Questions

Explore conceptually related problems

A capacitor having a capacitance of 100muF is chargeed to a potential difference of 24V . The charging bettery is disonnected and the capacitor is connected to another bettery of emf 12V with the positive plate of the capacitor joined with the positive terminal of the bettery . (a ) Find the charges on the capacitor before and after the reconnection . (b ) Find the charge flown through the 12V bettery . (c ) Is work done by the bettery or is it done on the bettery ? find its magnitude . (d ) Find the decrease is electrostatic field energy . (e ) Find the best developed during the flow of charge after reconnection.

A capacitor (C=50 muF) is charged to a potential difference of 20V . The charging battery is disconnected and the capacitor is connected to another cell of emf 10V with the positive plate of capacitor joined with the positive terminal of cell. (a) find charge flown through 10V cell. (b) is work done by the cell ot is it done on the cell? find its magnitude. (c) find the heat developed in connecting wires.

An ideal capacitor of capacitance 0.2muF is charged to a potential difference of 10V . The charging battery is than disconnected. The capacitor is then connected to an ideal inductor of self inductance 0.5mH . The current at a time when the potential difference across the capacitor is 5V is :

A capacitor having capacitance 'C' is charged by a battery having e.m.f. 2V (Battery is disconnected after charging). Now this charged capacitor is connected to another battery having e.m.f. V. The positive plate of capacitor is connected with -ve terminal of battery & vice-versa. The amount of heat produced after connecting it with battery. +q

A capacitor of capacitance C is charged to a potential difference V_(0) . The charged battery is disconnected and the capacitor is connected to a capacitor of unknown capacitance C_(x) . The potential difference across the combination is V. The value of C_(x) should be

A capacitor C is charged to a potential difference V and battery is disconnected. Now if the capacitor plates are brough close slowely by some distance:

A capacitor of capacitance 4 muF is fully charged to a potential difference of 12 V and then charging battery is disconnected. Charged capacitor is now connected across an inductor of self-inductance of 1.2 mH. The current in the circuit at a time when the potential difference across the capacitor is 6 V is

A capacitor of capacitance of 2muF is charged to a potential difference of 200V , after disconnecting from the battery, it is connected in parallel with another uncharged capacitor. The final common potential is 20V then the capacitance of second capacitor is :

A capacitor of capacitance 10 mu F is charged to a potential 50 V with a battery. The battery is now disconnected and an additional charge 200 mu C is given to the positive plate of the capacitor. The potential difference across the capacitor will be.

A 100pF capacitor is charged to a potential difference of 80.0V and the charging battery is disconnected. The capacitor is then connected in parallel with a second capacitor. If the potential difference across the first capacitor drops to 35.0 V what is the capacitance of this second capacitor?

Knowledge Check

  • An ideal capacitor of capacitance 0.2muF is charged to a potential difference of 10V . The charging battery is than disconnected. The capacitor is then connected to an ideal inductor of self inductance 0.5mH . The current at a time when the potential difference across the capacitor is 5V is :

    A
    `0.34 A`
    B
    `0.17 A`
    C
    `0.25 A`
    D
    `0.15A`

  • A capacitor of capacitance C is charged to a potential difference V_(0) . The charged battery is disconnected and the capacitor is connected to a capacitor of unknown capacitance C_(x) . The potential difference across the combination is V. The value of C_(x) should be

    A
    `(C(V_(0) - V))/(V)`
    B
    `(C(V - V_(0)))/(V)`
    C
    `(CV)/(V_(0))`
    D
    `(CV_(0))/(V)`

  • A capacitor C is charged to a potential difference V and battery is disconnected. Now if the capacitor plates are brough close slowely by some distance:

    A
    some `+ve` work is done by external agent
    B
    enegry of capacitor will decrease
    C
    enegry of capacitor will increase
    D
    none of the above