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If the curves y=2\ e^x and y=a e^(-x) in...

If the curves `y=2\ e^x` and `y=a e^(-x)` intersect orthogonally, then `a=` `1//2` (b) `-1//2` (c) `2` (d) `2e^2`

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`y = 2e^x`
Hence, `dy/dx = 2e^x = m_1`
Also, given that` y= ae^(-x)`
`dy/dx = -ae^(-x) = m_2 `
...
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