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Arrange the elements with the followin...

Arrange the elements with the following electronic configuration in order of increasing electron gain enthalpy
`(i) 1s^(2) 2s^(2) 2p^(5) (ii) 1s^(2) 2s^(2) 2p^(4) (iii) 1s^(2) 2s^(2) 2p^(3) (iv) 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(4)`

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To arrange the elements with the given electronic configurations in order of increasing electron gain enthalpy, we need to analyze the configurations and understand the concept of electron gain enthalpy. ### Step-by-Step Solution: 1. **Identify the Elements**: - (i) 1s² 2s² 2p⁵ corresponds to Fluorine (F). - (ii) 1s² 2s² 2p⁴ corresponds to Oxygen (O). - (iii) 1s² 2s² 2p³ corresponds to Nitrogen (N). - (iv) 1s² 2s² 2p⁶ 3s² 3p⁴ corresponds to Selenium (Se). 2. **Understand Electron Gain Enthalpy**: - Electron gain enthalpy is the energy change when an electron is added to a neutral atom in the gaseous state. A more negative value indicates a greater tendency to gain an electron. 3. **Consider Atomic Size and Electron Configuration**: - Smaller atoms with higher effective nuclear charge tend to have more negative electron gain enthalpy because they can attract additional electrons more effectively. - Half-filled and fully filled subshells are more stable, making it less favorable for these atoms to gain additional electrons. 4. **Analyze Each Element**: - **Fluorine (F)**: 1s² 2s² 2p⁵ - Needs 1 electron to achieve a stable octet. Has a high electron gain enthalpy (very negative). - **Oxygen (O)**: 1s² 2s² 2p⁴ - Needs 2 electrons to achieve a stable octet. Less negative than Fluorine. - **Nitrogen (N)**: 1s² 2s² 2p³ - Half-filled p subshell, so it is relatively stable and does not favor gaining electrons. Thus, it has a less negative electron gain enthalpy than both F and O. - **Selenium (Se)**: 1s² 2s² 2p⁶ 3s² 3p⁴ - Larger atomic size (third period) and less effective nuclear charge compared to the others, leading to the least negative electron gain enthalpy. 5. **Arrange in Order of Increasing Electron Gain Enthalpy**: - Based on the analysis: - Selenium (Se) has the least negative electron gain enthalpy. - Nitrogen (N) is next. - Oxygen (O) follows. - Fluorine (F) has the most negative electron gain enthalpy. ### Final Order: Increasing electron gain enthalpy: **Se < N < O < F**

To arrange the elements with the given electronic configurations in order of increasing electron gain enthalpy, we need to analyze the configurations and understand the concept of electron gain enthalpy. ### Step-by-Step Solution: 1. **Identify the Elements**: - (i) 1s² 2s² 2p⁵ corresponds to Fluorine (F). - (ii) 1s² 2s² 2p⁴ corresponds to Oxygen (O). - (iii) 1s² 2s² 2p³ corresponds to Nitrogen (N). ...
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Which of the following represent ground state configurations and which are excited state configurations. (i) 1s^(2), 2s^(2) 2p^(4) , (ii) 1s^(2)2s^(2)2p^(6)3s^(1)3p^(1) , (iii) 1s^(2) 2s^(2)2p^(6) 3s^(2)3p^(4) .

Predict total spin for each configuration : (A) 1s^(2) " " (B) 1s^(2),2s^(2),2p^(6) (C ) 1s^(2),2s^(2),2p^(5) " " (D) 1s^(2),2s^(2),2p^(3) (E) 1s^(2),2s^(2)2p^(6),3s^(2) 3p^(6)3d^(5),4s^(2)

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