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Arrange the elements with the followin...

Arrange the elements with the following electronic configuration in order of increasing electron gain enthalpy
`(i) 1s^(2) 2s^(2) 2p^(5) (ii) 1s^(2) 2s^(2) 2p^(4) (iii) 1s^(2) 2s^(2) 2p^(3) (iv) 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(4)`

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To arrange the elements with the given electronic configurations in order of increasing electron gain enthalpy, we need to analyze the configurations and understand the concept of electron gain enthalpy. ### Step-by-Step Solution: 1. **Identify the Elements**: - (i) 1s² 2s² 2p⁵ corresponds to Fluorine (F). - (ii) 1s² 2s² 2p⁴ corresponds to Oxygen (O). - (iii) 1s² 2s² 2p³ corresponds to Nitrogen (N). - (iv) 1s² 2s² 2p⁶ 3s² 3p⁴ corresponds to Selenium (Se). 2. **Understand Electron Gain Enthalpy**: - Electron gain enthalpy is the energy change when an electron is added to a neutral atom in the gaseous state. A more negative value indicates a greater tendency to gain an electron. 3. **Consider Atomic Size and Electron Configuration**: - Smaller atoms with higher effective nuclear charge tend to have more negative electron gain enthalpy because they can attract additional electrons more effectively. - Half-filled and fully filled subshells are more stable, making it less favorable for these atoms to gain additional electrons. 4. **Analyze Each Element**: - **Fluorine (F)**: 1s² 2s² 2p⁵ - Needs 1 electron to achieve a stable octet. Has a high electron gain enthalpy (very negative). - **Oxygen (O)**: 1s² 2s² 2p⁴ - Needs 2 electrons to achieve a stable octet. Less negative than Fluorine. - **Nitrogen (N)**: 1s² 2s² 2p³ - Half-filled p subshell, so it is relatively stable and does not favor gaining electrons. Thus, it has a less negative electron gain enthalpy than both F and O. - **Selenium (Se)**: 1s² 2s² 2p⁶ 3s² 3p⁴ - Larger atomic size (third period) and less effective nuclear charge compared to the others, leading to the least negative electron gain enthalpy. 5. **Arrange in Order of Increasing Electron Gain Enthalpy**: - Based on the analysis: - Selenium (Se) has the least negative electron gain enthalpy. - Nitrogen (N) is next. - Oxygen (O) follows. - Fluorine (F) has the most negative electron gain enthalpy. ### Final Order: Increasing electron gain enthalpy: **Se < N < O < F**

To arrange the elements with the given electronic configurations in order of increasing electron gain enthalpy, we need to analyze the configurations and understand the concept of electron gain enthalpy. ### Step-by-Step Solution: 1. **Identify the Elements**: - (i) 1s² 2s² 2p⁵ corresponds to Fluorine (F). - (ii) 1s² 2s² 2p⁴ corresponds to Oxygen (O). - (iii) 1s² 2s² 2p³ corresponds to Nitrogen (N). ...
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Arrange the following in the order of increasing ionization enthalpy : (i) 1 s^(2) 2s^(2) 2p^(6) 3s^(2) (ii) 1s^(2) 2s^(2) 2p^(6) 3s^(1) (iii) 1s^(2) 2s^(2) 2p^(6) (iv) 1s^(2) 2s^(2) 2p^(2) (v) 1s^(2) 2s^(2) 2p^(3)

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Knowledge Check

  • Arrange the elements with the following electronic configurations in increasing order of electron affinity (i) 1s^(2)2s^(2)2p^(5) (ii) 1s^(2)2s^(2)2p^(4) (iii) 1s^(2)2s^(2)2p^(6)3p^(4) (iv) 1s^(2)2s^(2)2p^(6)3s^(2)3p^(5)

    A
    `(ii) lt (iii) lt (i) lt (iv)`
    B
    `(iii) lt (ii) lt (iv) lt (i)`
    C
    `(iii) lt (ii) lt (i) lt (iv)`
    D
    `(iii) lt (ii) lt (i) lt (iv)`
  • Increasing order of Electron affinity for following configuration. (a) 1s^(2),2s^(2),2p^(2) (b) 1s^(2), 2s^(2) 2p^(4) (c) 1s^(2), 2s^(2), 2p^(6),3s^(2), 3p^(4) (d) 1s^(2), 2s^(2), 2p^(6), 3s^(2), 3p^(3)

    A
    d `lt` a`lt` b `lt` c
    B
    d `lt` a `lt` c `lt` b
    C
    a `lt` b `lt` c `lt` d
    D
    a `lt` b `lt` d `lt` c
  • The increasing order of electron affinity of the electronic configurations of element is :- (I) 1s^(2) 2s^(2)2p^(6)3s^(2)3p^(5) (II) 1s^(2) 2s^(2)2p^(3) (III) 1s^(2)2s^(2)2p^(5) (IV) 1s^(2)2s^(2)2p^(6) 3s^(1)

    A
    `II lt IV lt III lt I`
    B
    `I lt II lt III lt IV`
    C
    `I lt III lt II lt IV`
    D
    `IV lt III lt II lt I`
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