The compound `C_(4)H_(10)O` can show

Options

A. Metamerism
B. Functional isomerism
C. Position isomers
D. All the above

Answer

4

Explanation

`C_(4)H_(10)O,D.U.=O,` This is saturated compound, so it can be alcohol and ether.
`underset("Butan"-1-ol)(CH_(3)-CH_(2)-CH_(2)-CH_(2)-OH)" "underset("Butan"-2-ol)(CH_(3)-CH_(2)-underset(OH)underset(|)(CH)-CH_(3)),underset("Isobutanol")(CH_(3)-underset(CH_(3))underset(|)(CH)-CH_(2)-OH)`
`CH_(3)-CH_(2)-CH_(2)-O-CH_(3),CH_(3)-CH_(2)-O-CH_(2)-CH_(3)`
So, compound `C_(4)H_(10)O` can show position, functional and metamerism.