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What will be the volume strength of 100 ml of `H_(2)O_(2)` required to react completely with 61 ml of `KMnO_(4)` in acidic medium ? ( Given that `61 l` of `KMnO_(4)` reacts completely with 5 ml of 1M of `K_(4)[Fe(CN)_(6)]` where it converts into `K^(+),Fe^(3+),CO_(3)^(2-)` and `NO_(3)^(-)` )

A

`17.08`

B

`34.2`

C

`18.8`

D

`19.8`

Text Solution

Verified by Experts

The correct Answer is:
1
Valency factor of `K_(4)[(Fe(CN)_(6)]=61`
so of molarity of `H_(2)O_(2)=x M` than
`implies2x xx100=5xx61xx1`
`[` for `KMnO_(4). 61xxyxx5=5xx61xx1impliesy=1M]`

So, `x=(305)/(200)=1.525.` So , volume strength `=17.08`
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Knowledge Check

  • What will be the volume strength of 100mL of KMnO_4 in acidic medium? (Given that 61mL of KMnO_4 reacts completely with 5mL of 1MK_(4) [Fe(CN)_(6))] where it converts into K^(+),Fe^(3+),CO_(3)^(2-) and NO_(3)^(-))

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    0.5

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