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1 kg ice at -10^(@)C is mixed with 0.1 k...

`1 kg` ice at `-10^(@)C` is mixed with `0.1 kg` of steam at `200^(@)C`. If final temperature of mixture at equilibrium is `T_(eq)=(58x)/11`, then fill the vallue of `x`
Latent heat of fusion of ice `=80` cal/gram, latent heat of vaporization of water `=540` cal/gram, specific heat capacity of ice `~=` specific heat of water `=0.5` cal/gram-K`

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The correct Answer is:
5
`1xx 1/2 xx 10+1xx80+1xx1xxT_("eq")=0.1xx1/2xx100+0.1xx540+0.1xx(100-T_("eq"))`
`T_("eq")=290/11 K=58/11xx5`
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