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A hydrogen atom moving at a speed v(0) a...

A hydrogen atom moving at a speed `v_(0)` absorbs a photon of wavelength `61 nm` and stops. Mass of the hydrogen atom is `1.67xx10^(-27)kg`. When calculated `v_(0)` comes out to be `13/n m//s`. Find `n` nearly.

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The correct Answer is:
2
`1.67xx10^(-27)v_(0)=(6.62xx10^(-34))/(61xx10^(-9))impliesv_(0)=6.5m//simpliesn=2`
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Knowledge Check

  • A hydrogen atom moving at a speed v absorbs a photon of wavelength 122 nm and stops. The value of v is

    A
    2.75 m/s
    B
    3.25 m/s
    C
    4.85 m/s
    D
    5.65 m/s

  • A hydrogen atom moving at a speed v absorbs a photon of wavelength 122 nm and stops. The value of v is (mass of hydrogen atom =1.67xx10^(-27) kg)

    A
    `3.25 m//sec`
    B
    `6.25 m//sec`
    C
    `9.25 m//sec`
    D
    `12.25 m//sec`

  • The rest mass of a proton is 1.67xx10^(-27) kg Its total energy when it moves with a speed of 2.1 xx10^(8) m/s is

    A
    `2.105xx10^(-10) J`
    B
    `20.16xx10^(-10) J`
    C
    `2.105xx10^(-9) J`
    D
    `20.15xx10^(-9) J`

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