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A vessel containing 100 g ice at 0^(@)C ...

A vessel containing 100 g ice at `0^(@)C` is suspended in a room where temperature is `35^(@)C`. It was found that the entire ice melted in 10 hour. Now the same vessel containing 100 g of water at `0^(@)C` is suspended in the same room. How much time will it take for the temperature of water to rise to `0.5^(@)C`. Neglect the heat capacity of the vessel. Specific heat of water and specific latent heat of fusion of ice are `1 cal g^(-1) .^(@)C^(-1)` and `80 cal g^(-1)` respectively.

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The correct Answer is:
`3.75` min.
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A vessel containing 100g watera at 0^(@)C is suspended in the middle of a room. In 15 minutes the temperature of the water rises by 2^(@)C . When an equal amount of ice is placed in the vessel, it melts in 10 hours. Calculate the specific latent heat of fusion of ice.

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Knowledge Check

  • A piece of ice at 0^@C is added to a vessel containing water at 0^@C , then

    A
    all of the ice will melt
    B
    some ice will melt
    C
    no ice will melt
    D
    the temperature will decrease further
  • A mass m of steam at 100^(@)C is to passed into a vessel containing 10g of ice and 100g of water at 0^(@)C so that all the ice is melted and the temperature is raised to 5^(@)C neglecting heat absorbed by the vessel, we get

    A
    m = 2.1 g
    B
    m = 4.2 g
    C
    m = 6.3g
    D
    m = 8.4g
  • A piece of ice at 0^@C is put into a vessel containing water at 0^@C . The ice will

    A
    melt
    B
    not melt
    C
    slightly melt
    D
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    Steam at 100^@C is allowed to pass into a vessel containing 10g of ice and 100 g of water at 0^@C until all the ice is melted and the temperature is raised to 50^@C . Neglecting water equivalent of the vessel and the loss due to radiation etc. Calculate how much steam is condensed.

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