Home
Class 12
PHYSICS
Consider a semicircular ring with mass m...

Consider a semicircular ring with mass m and radius R as shown in figure.

Statement-1: The moment of inertia of semi - circular ring about an axis passing through A and perpendicular to plane is `2mR^(2)`
Statement-2: According to parallel axis theorem: `I_(A)=1_(cm)+mR^(2)`

A

Statement-1 is true, statement-2 is true and statement-2 is correct explanation for statement-1.

B

Statement-1 is true, statement-2 is true and statement-2 is NOT the correct explanation for statement-1.

C

Statement-1 is true, statement-2 is false.

D

Statement -1 is false, statement -2 is true.

Text Solution

Verified by Experts

The correct Answer is:
C
`I=(2mR^(2)+2mR^(2))/2` (due to symmetry)
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MASTER PRACTICE PROBLEM

    BANSAL|Exercise Multiple objective|131 Videos

  • MASTER PRACTICE PROBLEM

    BANSAL|Exercise Subjective|107 Videos

  • MASTER PRACTICE PROBLEM

    BANSAL|Exercise Comphrehension|134 Videos

  • FLUID MECHANICS

    BANSAL|Exercise PYQS AIEEE|10 Videos

  • SEMICONDUCTORS

    BANSAL|Exercise CBSE Question|32 Videos

Similar Questions

Explore conceptually related problems

Derive an expression for moment of inertia of a thin circular ring about an axis passing through its centre and perpendicular to the plane of the ring.

The moment of inertia of a circular ring about an axis passing through its centre and normal to its plane is 200 gm xx cm^(2) . Then moment of inertia about its diameter is

Knowledge Check

  • Moment of inertia of a circular ring about an axis through its centre and perpendicular to its plane is

    A
    `I = (1)/(2) MR^2`
    B
    `I = MR^2`
    C
    `I = (3)/(2) MR^2`
    D
    `I = (5)/(2) MR^2`

  • The moment of inertia of a circular ring of mass 1 kg about an axis passing through its centre and perpendicular to its plane is "4 kg m"^(2) . The diameter of the ring is

    A
    2 m
    B
    4 m
    C
    5 m
    D
    6 m

  • Moment of inertia of a ring of mass M and radius R about an axis passing through the centre and perpendicular to the plane is

    A
    `1//2MR^(2)`
    B
    `MR^(2)`
    C
    `1//4MR^(2)`
    D
    `3//4 MR^(2)`

    • Similar Questions

    Explore conceptually related problems

    Calculate the moment of Inertia of a semicircular disc of mass M and radius R about an axis passing through its centre and perpendicular to its plane.

    Calculate the moment of inertia of a disc of radius R and mass M, about an axis passing through its centre and perpendicular to the plane.

    From a ring of mass M and radius R, a 30^o sector is removed. The moment of inertia of the remaining portion of the ring, about an axis passing through the centre and perpendicular to the plane of the ring is

    Calculate the moment of inertia of a ring of mass 2 kg and radius 50 cm about an axis passing through its centre and perpendicular to its plane

    The mass of a uniform circular ring of radius 0.2m is 0.1kg . Calcuate the moment of inertia of the ring about an axis passing through its centre an perpendicular to its surface.

    Home
    Profile