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The dimensional formula for permeability...

The dimensional formula for permeability of free space, `mu_(0)` is

A

`[MLT^(-2)A^(-2)]`

B

`[ML^(-1)T^(2)A^(-2)]`

C

`[ML^(-1)T^(-2)A^(2)]`

D

`[MLT^(-2)A^(-1)]`

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To find the dimensional formula for the permeability of free space, denoted as \( \mu_0 \), we can start from the relationship given by Ampère's law in magnetostatics. The formula can be expressed in terms of magnetic field \( B \), current \( I \), and distance \( r \). 1. **Understanding the relationship**: The permeability of free space \( \mu_0 \) is related to the magnetic field \( B \) produced by a current \( I \) at a distance \( r \). The formula can be expressed as: \[ B = \frac{\mu_0 I}{2\pi r} \] Rearranging this gives: \[ \mu_0 = \frac{B \cdot 2\pi r}{I} \] 2. **Identifying dimensions**: - The dimension of magnetic field \( B \) is given as: \[ [B] = [M][T^{-2}][A^{-1}] \quad \text{(where M is mass, T is time, A is current)} \] - The dimension of current \( I \) is: \[ [I] = [A] \] - The dimension of distance \( r \) is: \[ [r] = [L] \] 3. **Substituting dimensions into the formula**: Now substituting the dimensions into the equation for \( \mu_0 \): \[ [\mu_0] = \frac{[B] \cdot [r]}{[I]} = \frac{[M][T^{-2}][A^{-1}] \cdot [L]}{[A]} \] 4. **Simplifying the expression**: This simplifies to: \[ [\mu_0] = [M][L][T^{-2}][A^{-2}] \] 5. **Final result**: Therefore, the dimensional formula for the permeability of free space \( \mu_0 \) is: \[ [\mu_0] = [M^1 L^1 T^{-2} A^{-2}] \]

To find the dimensional formula for the permeability of free space, denoted as \( \mu_0 \), we can start from the relationship given by Ampère's law in magnetostatics. The formula can be expressed in terms of magnetic field \( B \), current \( I \), and distance \( r \). 1. **Understanding the relationship**: The permeability of free space \( \mu_0 \) is related to the magnetic field \( B \) produced by a current \( I \) at a distance \( r \). The formula can be expressed as: \[ B = \frac{\mu_0 I}{2\pi r} \] Rearranging this gives: ...
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Knowledge Check

  • The dimensional formula for permittivity of free space (epsilon_0) in the equation F ==1/(4piepsilon_0),(q_1q_2)/(r^2) , where symbols have usual meaning is

    A
    `[M^1L^3A^(-2)T^(-4)]`
    B
    `[M^(-1)L^(-3)T^4A^2]`
    C
    `[M^(-1)L^(-3)A^(-2)T^(-4)]`
    D
    `[M^(1)L^(3)T^2A^(-4)]`
  • The dimensional formula for magnetic permeability mu is :

    A
    `[MLT^(-2)A^(-2)]`
    B
    `[M^(0)L^(-1)T]`
    C
    `[M^(0)L^(2)T^(-1) A^(2)]`
    D
    `[ML^(2)T^(-2)A^(-2)]`
  • The dimensional formula of permittivity (epsilon_0) of free space is :

    A
    `M^(-1)L^(-3) T^4A^2`
    B
    `M^(-1)L^(-2)T^2 A`
    C
    `M^(-1)L^(-2)T^(-2)A`
    D
    `M^(-1)L^(-2)T^(-2) A^(-2)`
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    The dimensional null formula of magnetic permeability is

    Let [epsi_(0)] denote the dimensional formula of the permittivity of the vacuum and [mu_(0)] that of the permeability of the vacuum. If M = mass, L = length, T = time and I = electric current :

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