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The bulk modulus of a spherical object i...

The bulk modulus of a spherical object is `B` if it is subjected to uniform pressure `P`, the fractional decrease in radius is:

A

`(p)/(B)`

B

`(B)/(3P)`

C

`(3P)/(B)`

D

`(P)/(3B)`

Text Solution

Verified by Experts

The correct Answer is:
D

The object is spherical and the bulk modulus is represented by B. It is the ratio of normal stress to the volumetric strain.
Hence `B = (F//A)/(Delta V//V) rArr (Delta V)/(V) = (p)/(B) rArr |(Delta V)/(V)| = (p)/(B)`
Here p is applied pressure on the object and `(Delta V)/(V)` is volume strain
Fractional decreases in volume
`rArr (Delta V)/(V) = 3(Delta R)/(R) " " [because V = (4)/(3)pi R^(3)]`
Volume of the sphere decreases due to the decreases in its radius.
Hence `(Delta V)/(V) = (3Delta R)/(R) = (p)/(R) rArr (Delta R)/(R) = (p)/(3B)`
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Knowledge Check

  • The bulk modulus of a spherical objects is 'B'. If it is subjected to uniform pressure 'P', the fractional decrease in radius is

    A
    `(B)/(3P)`
    B
    `(3P)/(B)`
    C
    `(P)/(3B)`
    D
    `(P)/(B)`
  • The bulk modulus of a sphericla objects is 'B'. If it is subjected to uniform pressure 'P', the fractional decrease in radius is

    A
    `(B)/(3P)`
    B
    `(3P)/(B)`
    C
    `(P)/(3B)`
    D
    `(P)/(B)`
  • A material has normal density rho and bulk modulus K . The increase in the density of the material when it is subjected to an external pressure P from all sides is

    A
    `P//rhoK`
    B
    `K//rhoP`
    C
    `rhoP//K`
    D
    `rhoK//P`
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