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Assuming the earth to be a sphere of uni...

Assuming the earth to be a sphere of uniform density, the acceleration due to gravity

A

at a point outside the earth is inversely proportional to the square of its distance from the centre

B

at a point outside the earth is inversely proportional to its disatance from the centre

C

at any point inside is zero

D

at a point inside is proportional to its distance from the centre.

Text Solution

Verified by Experts

The correct Answer is:
A, D
`g=(Gm)/(R^(3))xxr` for `r lt R`
`g = (Gm)/(r^(2))` for `r gt R`
so choice (A) and (D) are correct
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Knowledge Check

  • Assume the earth to be a sphere of uniform density the accleration due to gravity

    A
    at a point outside the earth is inversely proportional to the square of its distance from the centre
    B
    at a point outside the earth is inversely proportional to its distance from the centre
    C
    at a point inside is zero
    D
    at a point inside is proportional to its distance from the centre.

  • Assuming the earth as a sphere of unifonn density. the acceleration due to gravity half way towards the centre of the earth will be

    A
    0.75 g
    B
    0.50 g
    C
    0.25 g
    D
    0.125 g

  • Assuming earth to be a sphere of a uniform density, what is the value of gravitational acceleration in mine 100km below the earth's surface (Given R=6400km)

    A
    `9.66m//s^(2)`
    B
    `7.64m//s^(2)`
    C
    `5.06m//s^(2)`
    D
    `3.10m//s^(2)`

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