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Two soap bubbles of radii r(1) and r(2) ...

Two soap bubbles of radii `r_(1)` and `r_(2)` equal to 4 cm and 5 cm are touching each other over a common surface `S_(1)S_(2)` (shown in figure). Its radius will be

A

4 cm

B

20 cm

C

5 cm

D

4.5 cm

Text Solution

Verified by Experts

The correct Answer is:
B
`r=(r_(1)r_(2))/(r_(2)-r_(1))`
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Knowledge Check

  • When two soap bubbles of radius r_(1) and r_(2)(r_(2) gt r_(1)) coalesce, the radius of curvature of common surface is

    A
    `r_(2)-r_(1)`
    B
    `(r_(2)-r_(1))/(r_(1)r_(2))`
    C
    `(r_(1)r_(2))/(r_(2)-r_(1))`
    D
    `r_(2)+r_(1)`

  • Two soap bubbles each of radius r are touching each other. The radius of curvature of the common surface will be:

    A
    infinite
    B
    2r
    C
    `r`
    D
    `r//2`

  • Two soap bubbles of radii R_(1) and R_(2) kept in atmosphere are combined isothermally to form a big bubble of radius R. The expression for surface tension will be

    A
    `(P_(0)(R^(3)+R_(1)^(3)+R_(2)^(3)))/(4(R^(2)+R_(1)^(2)+R_(2)^(2)))`
    B
    `(P_(0)(R_(1)^(3)+R_(2)^(3)-R^(3)))/(4(R^(2)-R_(1)^(2)-R_(2)^(2)))`
    C
    `P_(0)(R_(1)^(3)+R_(2)^(3)-R^(3))`
    D
    `4P_(0)(R_(1)^(3)+R_(2)^(3)-R^(3))`

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    Under isothermal condition two soap bubbles of radii r_(1) and r_(2) coalesce to form a single bubble of radius r. The external pressure is p_(0) . Find the surface tension of the soap in terms of the given parameters.

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