Acceleration versus velocity graph of a particle moving in a straight line starting form rest is as shown in figure. The corresponding velocity-time graph would be :

Options

A.
B.
C.
D.

Answer

D

Explanation

From graph `a=-AV+B`
`(dV)/(dt)=-AV+B`
`int (dV)/((B-AV))=int dt`
`V=(B)/(A)(1-e^(-At))`