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In a potentiometer experiment , a partic...

In a potentiometer experiment , a particular cell produces balance in the wire at 560 cm . If a `10Omega` resistance is connected with the cell in parallel ,then this balanced lendth change to 412 cm . Find out the internal resistance of the cell .

Text Solution

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The correct Answer is:
`3.6oMEGA(APPROX),`
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Knowledge Check

  • When a resistance of 12 Omega is conencted with a cell of emf 1.5 V,0.1 A current flows through the resistance internal resistance of the cell is

    A
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    B
    `3 Omega`
    C
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    D
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  • n identical cells, each of emf e and internal resistance r, are first connected in series and then in parallel. What will be the ratio of the emfs and of the internal resistances of these two cell combinations?

    A
    n,n
    B
    `n,n^2`
    C
    `n^2,n`
    D
    `1/n,n`
  • In a potentiometer experiment, two cells connected in series get balanced at9 m length of the wire. Now, if the connections of terminals of cell of lower emf are reversed, then the balancing length is obtained at 3m. The ratio of emf's of two cells will be

    A
    `1:2`
    B
    `2:1`
    C
    `1:4`
    D
    `4:1`
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