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With a uniform potentimeter wire AB of ...

With a uniform potentimeter wire AB of resistance `100Omega` , an electric cell of emf 2 V of negligible internal resistance and voltmeter of `360 Omega` is connected in between the point A and a point C on the wire . If the reading in the voltemeter be 0.72 V then in what ratio does the point C divide the wire AB ?

Text Solution

Verified by Experts

The correct Answer is:
`2:3`
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With a uniform potentimeter wire AB of resistance 100Omega , an electric cell of negligible internal resistance and a voltmeter 360 Omega is connected in between A and the mid -point C of the wire . If the reading of the voltmeter be 1.0 V , determine the emf of the cell .

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Knowledge Check

  • The internal resistance of a cell of emf 1.5 V is 0.5 Omega A voltmeter of resistance 1 Omega is connected across it. The reading of the voltmeter will be :

    A
    1 V
    B
    1.5 V
    C
    0.5 V
    D
    0.3 V

  • A series combination of three resistances 1 Omega, 2 Omega and 3 Omega is connected with a cell of emf 1.5 V and of negligible internal resistance. What is the terminal potential difference across the third resistance?

    A
    `1/4 A`
    B
    `1/2 V`
    C
    `3/4 V`
    D
    `1 V`

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