Home
Class 12
PHYSICS
An astronomical telescope is adjusted to...

An astronomical telescope is adjusted to form the final image at infinity. The separation between the lenses is 80 cm . The angular magnification is 15 . Calculate the focal length of the eyepiece in cm.

Text Solution

Verified by Experts

The correct Answer is:
5
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • OPTICAL INSTRUMENTS

    CHHAYA PUBLICATION|Exercise EXAMINATION ARCHIVE With solutions|10 Videos
  • OPTICAL INSTRUMENTS

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|8 Videos
  • OPTICAL INSTRUMENTS

    CHHAYA PUBLICATION|Exercise ENTRANCE CORNER ( Comprehension type )|8 Videos
  • Magnetic Properties of Materials

    CHHAYA PUBLICATION|Exercise CBSE SCANNER|11 Videos
  • QUANTUM THEORY

    CHHAYA PUBLICATION|Exercise CBSE Scanner|29 Videos

Similar Questions

Explore conceptually related problems

The lengths of the tube of an astronomical telescope is 44 cm and its angular magnification is 10 . What is the focal length of its objective ?

The length of the tube of an astronomical telescope is 80 cm and the magnifying power of the instrument is 19 . Calculate the focal lengths of the objective and the eyepiece.

Knowledge Check

  • An astronomical refractive telescope has an objective of focal length 20 m and an eyepiece of focal length 2 cm .

    A
    The length of the telescope tube is 20.02 m
    B
    The magnification is 1000
    C
    The image formed is inverted
    D
    An objective of a larger aperture will increases the brightness and reduce chromatic aberration of the image
  • A Galileo's telescope has an objective of focal length 100 cm and magnifying power 50. The distance between the two lenses in normal adjustment is

    A
    106 cm
    B
    102 cm
    C
    92 cm
    D
    98 cm
  • Similar Questions

    Explore conceptually related problems

    To observe terrstrial bodies the angular magnification of a telescope is 5 . The distance between the objective and the eyepiece is 36 cm and the final image is formed at infinity . Determine the focal lengths of the objective lens and eyepiece lens.

    The focal lengths of the objective and the eyepiece of a compound microscope are 2m and 5 cm respectively. The distance between the two lenses is 20 cm . Final image is formed at 25 cm distance from the objective calculate the distance between eyepiece and final image.

    An object is placed at a distance of 5 cm from the objective of a compound microscope . If the final image is formed at the least distance of distinct vision and coincides with the object then calculate the focal lengths of the objective and the eyepiece . given that the least distance of distinct vision =25 cm and the magnifying power of the instrument = 15 cm.

    The focal lengths of the objective and the eyepiece of an astronomical telescope are 20 cm and 1 cm . If the instrument is focused for infinity and focused for distinct vision what will be the magnifying power ? What will be the length of the tube of the instrument in each case ?

    An object placed at a distance of 16cm from a convex lens produces an image of magnification m(m gt 1) . If the object is moved towards the lens by 8cm then again an image of magnification m is obtained. The numerical value of the focal length of the lens is

    A small astronomical telescope has an objective of focal length 50 cm and an eyepiece of focal length 5 cm . It is focussed at the sun and the final image is formed at a distance of 25 cm from the eyepiece . If the diameter of the sun subtends an angle of 32' at the centre of the objective calculate the angular magnification of the instrument and the actual size of the image.