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A rectangular loop of size lxxb carryin...

A rectangular loop of size `lxxb` carrying a steady current I is placed in a uniform magnetic field `vec(B)`. Prove that the torque `vec(tau)` acting on the loop is given by `vec(tau)=vec(m)xxvec(B) , "when " vec(m)` is the magnetic moment of the loop .

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Knowledge Check

  • A circular loop of wire is carrying a current I (as shown in the figure) o applying a uniform magnetic field inward perpendicular to the plane of the loop the loop

    A
    moves along the positive x direction
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