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If wavelength of light = lambda, width o...

If wavelength of light = `lambda`, width of aperture = a , then which one would show more distinct diffraction pattern among the following?
(i) When a = 5`lambda` ( ii) When a = 3`lambda`, and
(iii) When a `approx lambda`

Answer

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Knowledge Check

  • Wavelengths of microwave, ultraviolet and infrared rays are lambda_m,lambda_n and lambda_i , respectively. Which one of the following is correct?

    A
    `lambda_m gt lambda_n gt lambda_i`
    B
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    C
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    D
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  • In young' s double slit experiment, for the light of wavelength lambda_(1) fringe y_(1) and for the light of wavelength lambda_(2) fringe width is y_(2) . If the whole arrangement is dipped into a liquid of refractive index mu it is founded that for the wavelength lambda_(1) fringe width becomes y_(3) . Now the correct relation is Four light waves are represented by (i) y= a_(1) "sin" omega t " " (ii) y= a_(2) "sin" ( omega t+e) (iii) y= a_(1) "sin" 2 (omega t) " " (iv) y= a_(2) "sin" 2 (omega t +e)

    A
    `y_(2)=y_(1)(lambda_(1))/(lambda_(2))`
    B
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