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Electron used in an electron microscope ...

Electron used in an electron microscope are accelerated by a voltage of 25 kV. If the voltage is increased to 100 kV then the de Broglie wavelength associated with the electrons would

A

increase by 2 times

B

decrease by 2 times

C

decrease by 4 times

D

increase by 4 times

Text Solution

Verified by Experts

The correct Answer is:
B
We know, `lamda = (h)/(sqrt(2mE))`
where, E = qV [q = charge of electron, V = potential difference]
`:. (lamda_(1))/(lamda_(2)) = sqrt((E_(2))/(E_(1))) = sqrt((100)/(25))`
[here, `E_(1) = 25 kV and E_(2) = 100 kv`]
or, `(lamda_(1))/(lamda_(2)) = 2 or, lamda_(2) = (lamda_(1))/(2)`
The de Broglie wavelength linked with the electrons will be half
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Knowledge Check

  • An electron of mass m and a photon have same energy E. The ratio of de Broglie wavelength associated with them is

    A
    `((E)/(2m))^(1//2)`
    B
    `c(2mE)^(1//2)`
    C
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    D
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    B
    9 times
    C
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    D
    1/9 times

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