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Using Rutherford model of atom , derive ...

Using Rutherford model of atom , derive the expression for the total energy of the electron in hydrogen atom. What is the significance of total negative energy possessed by the electron ?

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Coulomb attractive force between the nucleus (proton ) of charge +e and the electron of charge -e is
`F=1/(4piin_0)*(e^2)/(r^2)=(k)/(r^2) ("say")`
We assume the proton to be too heavy compared to the electron . Then the proton remains stationary when the electron revolves in a circular orbit of radius r with velocity v

The force F provides the centripetal force `(mv^2)/(r)` for this revolution (m=electron mass).
`therefore (mv^2)/(r) =k/(r^2)`
The kinetic energy ,
`E_k=1/2 mv62=k/(2r)`
The potential energy = work done to bring the electron from an infinite distance , i.e.,
`E_p=int_(oo)^r k/(r^2)dr=k[-1/r]_(oo)^r=-k/r`
`therefore` Total energy,
`E=E_k+E_p=k/(2r)-k/r=-k/(2r)=-1/(4piin_0)*(e^2)/(2r)`
This negative of E suggest that the electron is bound in hydrogen atom. An equal amount of positive energy is to be supplied from outside to make the total energy of the electron to be zero. Then the electron will be free from the atom.
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Knowledge Check

  • The total energy of an electron in the ground state , of hydrogen atom is

    A
    zero
    B
    13.6 eV
    C
    `-13.6 eV`
    D
    `-13.6 J`
  • The ratio of kinetic energy of the total energy of an electron in a Bohr orbit of the hydrogen atom, is

    A
    `2:-1`
    B
    `1:-1`
    C
    `1:1`
    D
    `1:-2`
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