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PCl5 decomposes as PCl5(g) hArr PCl3(g)+...

`PCl_5` decomposes as `PCl_5(g) hArr PCl_3(g)+Cl_2(g)`.If at equilibrium , total pressure is P and density of gaseous mixture is d at temperature T then degree of dissociation `(alpha)` is :
(Molecular wt. of `PCl_5=M`)

A

`alpha=1-(PM)/(dRT)`

B

`alpha=1-(dRT)/(PM)`

C

`alpha=(PM)/(dRT)-1`

D

`alpha=(dRT)/(PM)-1`

Text Solution

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The correct Answer is:
C
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