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Assume that 10^(-17)J of light energy is...

Assume that `10^(-17)`J of light energy is needed by the interior of the human eye to see an object . How many photons of green light `(lambda = 495nm)` are needed to generate this minimum energy .
`[h=6.6xx10^(-34) Js]`

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To solve the problem, we need to determine how many photons of green light (with a wavelength of 495 nm) are required to generate a minimum energy of \(10^{-17}\) J. ### Step-by-Step Solution: 1. **Understand the Energy of a Single Photon**: The energy \(E\) of a single photon can be calculated using the formula: \[ E = \frac{hc}{\lambda} \] where: - \(h = 6.6 \times 10^{-34} \, \text{Js}\) (Planck's constant), - \(c = 3 \times 10^8 \, \text{m/s}\) (speed of light), - \(\lambda = 495 \, \text{nm} = 495 \times 10^{-9} \, \text{m}\) (wavelength of green light). 2. **Calculate the Energy of a Single Photon**: Substitute the values into the formula: \[ E = \frac{(6.6 \times 10^{-34} \, \text{Js})(3 \times 10^8 \, \text{m/s})}{495 \times 10^{-9} \, \text{m}} \] Now, calculate the numerator: \[ 6.6 \times 10^{-34} \times 3 \times 10^8 = 1.98 \times 10^{-25} \, \text{Jm} \] Now, divide by the wavelength: \[ E = \frac{1.98 \times 10^{-25}}{495 \times 10^{-9}} \approx 4.00 \times 10^{-19} \, \text{J} \] 3. **Determine the Number of Photons Needed**: To find the number of photons \(N\) required to generate the minimum energy \(E_{\text{total}} = 10^{-17} \, \text{J}\), use the formula: \[ N = \frac{E_{\text{total}}}{E} \] Substitute the values: \[ N = \frac{10^{-17}}{4.00 \times 10^{-19}} \approx 25 \] ### Final Answer: The number of photons of green light needed to generate the minimum energy is approximately **25**. ---
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Knowledge Check

  • Suppose 10^17 J of energy is needed by the interior of human eye to see an object. How many photons of green light (1 = 550 nm) are needed to generate this minimum amount of energy ?

    A
    14
    B
    28
    C
    39
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    42
  • If 10^(-17)J of energy from monochromatic light is needed by the interior of the human eye to see an object. How many photon of green light lambda = 550nm are needed to generate this min amount of energy ?

    A
    27
    B
    28
    C
    29
    D
    30
  • If 10^(-17)J of light energy is needed by the interior of human eye to see an object. The number of photons of green light (l=550 nm) needed to see the object are:

    A
    27
    B
    28
    C
    29
    D
    30
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