A mixture pf `H_(2) , N_(2)` and `O_(2)` occupying 100 ml underwent reaction so as to form `H_(2)O_(2)(l)` and `N_(2)H_(2)(g)` as the only products , causing the volume to contract by 60 ml. The remaining mixture was passed through pyrogallol causing a contraction of 10 ml . to the remaining mixture excess `H_(2)` was added and the above reaction was repeaped , causing a reduction in volume of 10 ml .(No other products are formed)
What is the volume of `N_(20H_(2)(g)` formed in this reaction after adding excess of `H_(2)(g)`?

Options

A. 20 ml
B. 30 ml
C. 10 ml
D. 40 ml

Answer

C