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According to the Avogadro's law , equal ...

According to the Avogadro's law , equal number of moles of gases occupy the same volume at identical conditions of temperature and pressure. Even if we have a mixture of non-reacting gases then Avogadro's law is still obeyed by assuming mixture as a new gas.
Now let us assume air to consist of 80% by volume of nitrogen `(N_(2))` and 20% by volume of oxygen `(O_(2))` . If air is taken at STP , then its 1 mol would occupy 22.4 L . 1 mol of air would contain 0.8 mol of `N_(2)` and 0.2 mol of `O_(2)` hence the mole fraction of `N_(2)` and `O_(2)` are given by `X_(n_(2))=0.8, X_(o_(2))=0.2`
Volume occupied by air at STP containing exactly 11.2 gm f nitrogen:

A

22.4 L

B

8.96 L

C

11.2 L

D

2.24 L

Text Solution

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The correct Answer is:
C
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Knowledge Check

  • According to the Avogadro's law , equal number of moles of gases occupy the same volume at identical conditions of temperature and pressure. Even if we have a mixture of non-reacting gases then Avogadro's law is still obeyed by assuming mixture as a new gas. Now let us assume air to consist of 80% by volume of nitrogen (N_(2)) and 20% by volume of oxygen (O_(2)) . If air is taken at STP , then its 1 mol would occupy 22.4 L . 1 mol of air would contain 0.8 mol of N_(2) and 0.2 mol of O_(2) hence the mole fraction of N_(2) and O_(2) are given by X_(n_(2))=0.8, X_(o_(2))=0.2 Density of air at STP is:

    A
    1 g/L
    B
    `(9)/(7) g//L`
    C
    `(2)/(7)g//L`
    D
    can't be determined

  • According to the Avogadro's law , equal number of moles of gases occupy the same volume at identical conditions of temperature and pressure. Even if we have a mixture of non-reacting gases then Avogadro's law is still obeyed by assuming mixture as a new gas. Now let us assume air to consist of 80% by volume of nitrogen (N_(2)) and 20% by volume of oxygen (O_(2)) . If air is taken at STP , then its 1 mol would occupy 22.4 L . 1 mol of air would contain 0.8 mol of N_(2) and 0.2 mol of O_(2) hence the mole fraction of N_(2) and O_(2) are given by X_(n_(2))=0.8, X_(o_(2))=0.2 If air is treated as a solution of O_(2) and N_(2) , then % w/w of oxygen is:

    A
    `(10)/(9)`
    B
    `(200)/(9)`
    C
    `(700)/(9)`
    D
    `(350)/(9)`

  • According to Avogadro's law , the volume percentages are equal to

    A
    mass percentages
    B
    number percentages
    C
    mole percentages
    D
    none of these

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