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632 g of sodium thiosulphate (a(2)S(2)O...

632 g of sodium thiosulphate `(a_(2)S_(2)O_(3))` reacts with copper sulphate to form cuproc thiosulphate which is reduced by sodium thiosulphate to give cuprous compound which is dissolved in excess of sodium thiosulphate to form a complex compound sodium cuprothisosulphate `(Na_(4)[Cu_(6)(S_(2)O_(3))_(5)])`, (MW=1033)
`CuSO_(4) + Na_(2)S_(2)O_(3) rarr CuS_(2)O_(3) + Na_(2)SO_(4)" "` [very fast]
`2CuSO_(4)+Na_(2)S_(2)O_(3)+Na_(2)S_(2)O_(3) rarr Cu_(2)S_(2)O_(3) + Na_(2)S_(4)O_(6)`
`3Cu_(2)S_(2)O_(3) + 2Na_(2)S_(2)O_(3) rarr Na_(4)[Cu_(6)(S_(2)O_(3))_(5)]`
`" "` (Sodium cuprothisoulphate )
In this process , 0.2 mole of sodium cuprothiosulphate is formed .(O=16 , Na=23 , S=32)
Moles of sodium thiosulophate reacted and unreacted after the reaction are respectively,

A

3 and 2

B

2 and 3

C

2.2 and 1.8

D

1.8 and 2.2

Text Solution

Verified by Experts

The correct Answer is:
C
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Maximum mole of Na_(4)[Cu_(6)(S_(2)O_(3))_(5)] which can be produced by 6 moles of CuSO_(4) and 10 moles of Na_(2)S_(2)O_(3) using following series of reaction- CuSO_(4)+Na_(2)S_(2)O_(3) to CuS_(2)O_(3)+Na_(2)SO_(4) 2CuS_(2)O_(3)+Na_(2)S_(2)O_(3) to Cu_(2)S_(2)O_(3)+Na_(2)S_(4)O_(6) 3Cu_(2)S_(2)O_(3)+2Na_(2)S_(2)O_(3) to Na_(4)[Cu_(6)(S_(2)O_(3))_(5)] Fill your answer to nearest integer.

AgI darr+2Na_(2)S_(2)O_(3) to Na_(3)[Ag(S_(2)O_(3))_(2)]+NaI

Knowledge Check

  • 632 g of sodium thiosulphate (a_(2)S_(2)O_(3)) reacts with copper sulphate to form cuproc thiosulphate which is reduced by sodium thiosulphate to give cuprous compound which is dissolved in excess of sodium thiosulphate to form a complex compound sodium cuprothisosulphate (Na_(4)[Cu_(6)(S_(2)O_(3))_(5)]) , (MW=1033) CuSO_(4) + Na_(2)S_(2)O_(3) rarr CuS_(2)O_(3) + Na_(2)SO_(4)" " [very fast] 2CuSO_(4)+Na_(2)S_(2)O_(3)+Na_(2)S_(2)O_(3) rarr Cu_(2)S_(2)O_(3) + Na_(2)S_(4)O_(6) 3Cu_(2)S_(2)O_(3) + 2Na_(2)S_(2)O_(3) rarr Na_(4)[Cu_(6)(S_(2)O_(3))_(5)] " " (Sodium cuprothisoulphate ) In this process , 0.2 mole of sodium cuprothiosulphate is formed .(O=16 , Na=23 , S=32) It instead of given amount of sodium thiosulphate, 2 moles of sodium thiosulphate along with 3 moles of CuSO_(4) were taken initially . Then, moles of sodiu cuprothiosulphate formed is:

    A
    0
    B
    1
    C
    1.5
    D
    2

  • S_(8)+NaOH to Na_(2)S+Na_(2)S_(2)O_(3)

    A
    For disproportionation reaction.
    B
    For comproportionation reaction.
    C
    For either intermolecular redox reaction or displacement reaction
    D
    For either thermal combination redox reaction or thermal decomposition redox reaction.

  • S_(8)+NaOH to Na_(2)S+Na_(2)S_(2)O_(3)

    A
    For disproportionation reaction.
    B
    For comproportionation reaction.
    C
    For either intermolecular redox reaction or displacement reaction
    D
    For either thermal combination redox reaction or thermal decomposition redox reaction.

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    632 g of sodium thiosulphate (Na_2S_2O_3) reacts with copper sulphate to form cupric thiosulphate which is reduced sodium thiosulphate to give cupros compound which is dissolved in excess of sodium thiosulphate to form a complex compound sodium cuprothiosulphate (Na_4[Cu_6(S_2O_3)_5]) . CuSO_4+Na_2S_2O_3toCuS_2O_3+Na_2SO_4 2CuS_2O_3+Na_2S_2O_3toCu_2S_2O_3+Na_2S_4O_6 3Cu_2S_2O_3+2Na_2S_2O_3to underset("Sodium cuprothiosulphate")(Na_4[Cu_6(S_2O_3)_5]) In this process, 0.2 moles of sodium cuprothiosulphate is formed. (O=16, Na=23, S=32) The average oxidation states of sulphur in Na_2S_2O_3 and Na_2S_4O_6 are respectively.

    Na_(2)S_(2)O_(3)+BaCl_(2) to BaS_(2)O_(3)darr+2NaCl

    Na_(2)S_(2)O_(3) is formed when

    Na_(2)S_(2)O_(3) is prepared by :

    Na_(2)S_(2)O_(3)+I_(2)rarr Product is

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