For the given series of reaction, 4NH(...

For the given series of reaction,
`4NH_(3)(g) + 5O_(2)(g) rarr 4NO(g) + 6H_(2)O(l)`
`2NO(g) + O_(2)(g) rarr 2NO(g) +O_(2)(g) rarr 2NO_(2)(g)` If 20 ml of `NH_(3)` is mixed with 100 ml of `O_(2)` .Volume contraction at the completion of above reaction is:

20 ml

85 ml

35 ml

100 ml

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For the given series of reaction, 4NH_(3)(g) + 5O_(2)(g) rarr 4NO(g) + 6H_(2)O(l) 2NO(g) + O_(2)(g) rarr 2NO(g) +O_(2)(g) rarr 2NO_(2)(g) Total volume of O_(2) used if 20 ml NH_(3) is mixed with 100 ml O_(2) is :

none of these

`(4)/(7)`

`(17)/(56)`

`(17)/(40)`

none of these

`-(d[NH_3])/(dt) =-(d[O_2])/(dt)=-(d[NO])/(dt)=-(d[H_2O])/(dt)`

`(d[NH_3])/(dt) =(d[O_2])/(dt)=-1/4(d[NO])/(dt)=-1/6(d[H_2O])/(dt)`

`1/4(d[NH_3])/(dt) =1/5(d[O_2])/(dt)=1/4(d[NO])/(dt)=1/6(d[H_2O])/(dt)`

`-1/4(d[NH_3])/(dt) =-1/5(d[O_2])/(dt)=1/4(d[NO])/(dt)=1/6(d[H_2O])/(dt)`