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H(2)O(2) solution of 45.4 V at STP . In ...

`H_(2)O_(2)` solution of 45.4 V at STP . In a hospital of Kota, patient under artifical respiration take s200ml `O_(2)` per min at 1 atm and 273 K and a cylinder last for 2.8 hours . After that it cannot be used for respiration though it still contains `H_(2)O_(2)` .
[Assume volume of solution and rate of decomposition remain constant]
Volume strenght of `H_(2)O_(2)` left in solution is:

A

11.35 V

B

22.7 V

C

5.67 V

D

34.05 V

Text Solution

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The correct Answer is:
D
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Knowledge Check

  • H_(2)O_(2) solution of 45.4 V at STP . In a hospital of Kota, patient under artifical respiration take s200ml O_(2) per min at 1 atm and 273 K and a cylinder last for 2.8 hours . After that it cannot be used for respiration though it still contains H_(2)O_(2) . [Assume volume of solution and rate of decomposition remain constant] Initial moles of H_(2)O_(2) in a cylinder are:

    A
    12
    B
    16
    C
    8
    D
    24
  • H_(2)O_(2) solution of 45.4 V at STP . In a hospital of Kota, patient under artifical respiration take s200ml O_(2) per min at 1 atm and 273 K and a cylinder last for 2.8 hours . After that it cannot be used for respiration though it still contains H_(2)O_(2) . [Assume volume of solution and rate of decomposition remain constant] Volume of oxygen used for respiration is :

    A
    11.2 L
    B
    22.4 L
    C
    33.6 L
    D
    5.6 L
  • The volume strenght of 3.0 M H_(2)O_(2) solution is

    A
    1.87
    B
    3.73
    C
    16.8
    D
    33.6
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