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Suppose the mass of a single Ag atom is ...

Suppose the mass of a single Ag atom is 'm'. Ag metal crystallises in fcc lattice with unit cell of length 'a'. The density of Ag metal in terms of 'a' and 'm' is-

A

`(4m)/a^(3)`

B

`(2m)/a^(3)`

C

`(m)/a^(3)`

D

`(m)/(4a^(3))`

Text Solution

Verified by Experts

The correct Answer is:
A
Volume of unit cell = `a^(3)`, no. of atoms present in fcc unit cell = `4xxm`. Thus, the density of the Ag metal = `(4m)/a^(3)`.
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Knowledge Check

  • A metal crystallises with a face-centred cubic lattice. The edge of the unit cell is 408pm. The diameter of the metal atom is-

    A
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    B
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    C
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    D
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