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The density of 3(M) solution of NaCl is ...

The density of 3(M) solution of NaCl is `1.25g*cm^(-3)` calculate the molality of the solution.

Text Solution

Verified by Experts

Amount of `NaCl` in 1L solution=3 mol=`3x58.5g`
Mass of 1 L solution`=1000xx1.25g=1250`
Mass of the solvent (i.e., water) in 1 L of the solution
`=(1250-175.5)=1074.5g`
`therefore`Molality`=("no. of moles of solute")/("mass of solvent (kg)")=(3)/(1.0745)=2.79(M)`
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