Home
Class 11
CHEMISTRY
The electronic transition from n=2 to n=...

The electronic transition from n=2 to n=1 will produce shortest wavelength in (where n=principal quantum state)-

A

`Li^(2+)`

B

`He^(2+)`

C

`H`

D

`H^(+)`

Text Solution

Verified by Experts

The correct Answer is:
A
`(1)/(lamda)=Z^(2)*R_(H)[(1)/(1^(2))-(1)/(2^(2))]=(3)/(4)R_(H)Z^(2)" Therefore, "lamdaprop(1)/(Z^(2))`
So, higher the value of Z, shorter will be the value of wavelength, thus `Li^(2+)` will have shorter wavelength.
Promotional Banner

Topper's Solved these Questions

  • STRUCTURE OF ATOM

    CHHAYA PUBLICATION|Exercise MCQ HOTSPOT (SINGLE CORRECT TYPE)|68 Videos

  • STRUCTURE OF ATOM

    CHHAYA PUBLICATION|Exercise EXERCISE (VERY SHORT TYPE QUESTION)|33 Videos

  • STRUCTURE OF ATOM

    CHHAYA PUBLICATION|Exercise HIGHER ORDER THINKING SKILL (HOTS) QUESTIONS|19 Videos

  • STATES OF MATTER : GASES AND LIQUIDS

    CHHAYA PUBLICATION|Exercise PRACTICE SET|10 Videos

Similar Questions

Explore conceptually related problems

The electronic transition from n=2 to n=1 will produce shortest wavelength in (where n= principal quantum number)

(1) Show that the sum of energies for the transition from n=3 to n=2 and from n=2 to n=1 is equal to the energy of transition from n=3 to n=1 in case of an H-atom. (2) Are wavelength and frequencies of the emitted spectrum also additive as their energies?

Electron in a hydrogen atom undergoes transition from n_1 to n_2 , where n_1 and n_2 are the principal quantum numbers of two given states. According to Bohr's theory , if the time period of the electron in the initial state be eight times that in the final state , the possible values of n_1 and n_2 will be, respectively

The electron in a hydrogen atom makes a transition n_1 to n_2 , where n_1 and n_2 are the principal quantum numbers of the two states. According to the Bohr model , the time period of revolution of electron in initial state is 8 times that in the final state. Which are possible values of n_1 and n_2 ? A 4,2 , B 8,2 , C 8,1 ,D 6,3 .

H, He^(+), Li^(2+) are examples of atoms or ions with one electron each . The energy of such atoms when in the n-th energy state (according to Bohr,s theory , n=1,2,3…. =principal quantum number ) is E_n =(-13.6 Z^2)/(n^2) eV (1 eV =1.6xx10^(-19)J) . For the ground state ,n=1 . in order to raise the atom from the ground state to n=f , the suitable incident light should have a wavelength given by lambda=(hc)/(E_f-E_1) . But the atom cannot stay permanently in the f-energy state, ultimately , it comes to the ground state by radiating the extra energy , E_f-E_1 as electromagnetic radiation . The electron of the atom comes from n=f to n=1 in one or more steps using the permitted energy levels . As a result there is a possibility of emission of radiation with more than one wavelength from the atom. Planck's constant =6.63 xx10^(-34)J*s and velocity of light c=3xx10^(8)m*s^(-1) . The wavelength of radiation emitted for the transition of the electron of He^+ ion from n=4 to n=2 is

H, He^(+), Li^(2+) are examples of atoms or ions with one electron each . The energy of such atoms when in the n-th energy state (according to Bohr,s theory , n=1,2,3…. =principal quantum number ) is E_n =(13.6 Z^2)/(n^2) eV (1 eV =1.6xx10^(-19)J) . For the ground state ,n=1 . in order to raise the atom from the ground state to n=f , the suitable incident light should have a wavelength given by lambda=(hc)/(E_f-E_1) . But the atom cannot stay permanently in the f-energy state, ultimately , it comes to the ground state by radiating the extra energy , E_f-E_1 as electromagnetic radiation . The electron of the atom comes from n=f to n=1 in one or more steps using the permitted energy levels . As a result there is a possibility of emission of radiation with more than one wavelength from the atom. Planck's constant =6.63 xx10^(-34)J*s and velocity of light c=3xx10^(8)m*s^(-1) . For what wavelength of incident radiation He^+ ion will be raised to fourth quantum state from ground state?

H, He^(+), Li^(2+) are examples of atoms or ions with one electron each . The energy of such atoms when in the n-th energy state (according to Bohr,s theory , n=1,2,3…. =principal quantum number ) is E_n =(-13.6 Z^2)/(n^2) eV (1 eV =1.6xx10^(-19)J) . For the ground state ,n=1 . in order to raise the atom from the ground state to n=f , the suitable incident light should have a wavelength given by lambda=(hc)/(E_f-E_1) . But the atom cannot stay permanently in the f-energy state, ultimately , it comes to the ground state by radiating the extra energy , E_f-E_1 as electromagnetic radiation . The electron of the atom comes from n=f to n=1 in one or more steps using the permitted energy levels . As a result there is a possibility of emission of radiation with more than one wavelength from the atom. Planck's constant =6.63 xx10^(-34)J*s and velocity of light c=3xx10^(8)m*s^(-1) . (i)What is the wavelength of the light incident on the atom to raise it to the fourth quantum level from ground state ?

H, He^(+), Li^(2+) are examples of atoms or ions with one electron each . The energy of such atoms when in the n-th energy state (according to Bohr,s theory , n=1,2,3…. =principal quantum number ) is E_n =(-13.6 Z^2)/(n^2) eV (1 eV =1.6xx10^(-19)J) . For the ground state ,n=1 . in order to raise the atom from the ground state to n=f , the suitable incident light should have a wavelength given by lambda=(hc)/(E_f-E_1) . But the atom cannot stay permanently in the f-energy state, ultimately , it comes to the ground state by radiating the extra energy , E_f-E_1 as electromagnetic radiation . The electron of the atom comes from n=f to n=1 in one or more steps using the permitted energy levels . As a result there is a possibility of emission of radiation with more than one wavelength from the atom. Planck's constant =6.63 xx10^(-34)J*s and velocity of light c=3xx10^(8)m*s^(-1) . Energy of which quantum state of He^+ ion will be equal to the ground level energy of hydrogen ?

Knowledge Check

  • The electronic transition from n=2 to n=1 will produce shortest wavelength in (where n= principal quantum number)

    A
    `Li^(2+)`
    B
    `He^+`
    C
    H
    D
    `H^+`

  • Electron in a hydrogen atom undergoes transition from n_1 to n_2 , where n_1 and n_2 are the principal quantum numbers of two given states. According to Bohr's theory , if the time period of the electron in the initial state be eight times that in the final state , the possible values of n_1 and n_2 will be, respectively

    A
    4 and 2
    B
    8 and 2
    C
    8 and 1
    D
    6 and 4

  • H, He^(+), Li^(2+) are examples of atoms or ions with one electron each . The energy of such atoms when in the n-th energy state (according to Bohr,s theory , n=1,2,3…. =principal quantum number ) is E_n =(-13.6 Z^2)/(n^2) eV (1 eV =1.6xx10^(-19)J) . For the ground state ,n=1 . in order to raise the atom from the ground state to n=f , the suitable incident light should have a wavelength given by lambda=(hc)/(E_f-E_1) . But the atom cannot stay permanently in the f-energy state, ultimately , it comes to the ground state by radiating the extra energy , E_f-E_1 as electromagnetic radiation . The electron of the atom comes from n=f to n=1 in one or more steps using the permitted energy levels . As a result there is a possibility of emission of radiation with more than one wavelength from the atom. Planck's constant =6.63 xx10^(-34)J*s and velocity of light c=3xx10^(8)m*s^(-1) . The wavelength of radiation emitted for the transition of the electron of He^+ ion from n=4 to n=2 is

    A
    952 Å
    B
    975 Å
    C
    1027 Å
    D
    1219 Å
    • CHHAYA PUBLICATION-STRUCTURE OF ATOM-ENTRANCE QUESTION BANK
    1. The electronic transition from n=2 to n=1 will produce shortest wavele...

      Text Solution

      |

    2. The representation of the ground state electronic configuration of He ...

      Text Solution

      |

    3. The energy of an electron if first Bohr orbit of H-atom is -13.6eV. Th...

      Text Solution

      |

    4. Which of the following does not represent the mathematical expression ...

      Text Solution

      |

    5. Identify the correct statement-

      Text Solution

      |

    6. The electronic configuration of Cu is-

      Text Solution

      |

    7. As per de Broglie's formula a macroscopic particle of mass 100 gm and ...

      Text Solution

      |

    8. The emission spectrum of hydrogen discovered first an the region of th...

      Text Solution

      |

    9. (""(32)Ge^(76),""(34)Se^(76)) and (""(14)Si^(30),""(16)S^(32)) are exa...

      Text Solution

      |

    10. The atomic number of cerium (Ce) is 58. the correct electronic configu...

      Text Solution

      |

    11. The time taken for an electron to complete one revolution in Bohr orbi...

      Text Solution

      |

    12. The energy required to break one mole of hydrogen-hydrogen bonds in H(...

      Text Solution

      |

    13. Identify the correct statement(s): the findings from the Bohr model of...

      Text Solution

      |

    14. Which one of the following corresponds to a photon of highest energy-

      Text Solution

      |

    15. Which of the following sets of quantum numbers represents the 19th ele...

      Text Solution

      |

    16. If the given four electronic configuration (i) n=4, l=1 (ii) n=4, ...

      Text Solution

      |

    17. The number of unpaired electrons in Ni (atomic number=28) are-

      Text Solution

      |

    18. Which of the following electronic configuration is not possible-

      Text Solution

      |

    19. The nucleus ""(29)^(64)Cu accepts an orbital electron to yield-

      Text Solution

      |

    20. Outer electronic configuration of Gd (atomic no: 64) is-

      Text Solution

      |