Calculate the kinetic energy of a moving electron associated with a wavelength of 4.8 pm.

Explanation

`v=(h)/(mlamda)=(6.626xx10^(-34)kg*m^(2)*s^(-1))/((9.11xx10^(-31)kg)xx(4.8xx10^(-12)m))`
`=1.51xx10^(8)m*s^(-1)`
`therefore`Kinetic energy
`=(1)/(2)xx(9.11xx10^(-31)kg)xx(1.51xx10^(8)m*s^(-1))^(2)`
`=1.38xx10^(-14)J`.