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Dipole moment of NaCl is 8.5 D. interato...

Dipole moment of NaCl is 8.5 D. interatomic distance between `Na^(+) and Cl^(-)` is 2.36 Å. Calculate the percentage of ionic character of NaCl molecule.

Text Solution

Verified by Experts

If NaCl is 100% ionic then,
`mu_(Na^(+)Cl^(-))=exxd=4.8xx10^(-10)esuxx2.36`Å
`=4.8xx10^(-10)esuxx2.36xx10^(-8)cm=11.328`D
`therefore%` Ionic character`=(mu_("observed"))/(mu_("ionic"))xx100=(8.5xx100)/(11.328)=75.035`
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Knowledge Check

  • The experimental value of the dipole moment of HCl is 1.03D. The length of the H-CI bond is 1.275 A. The percentage of ionic character in HCl is:

    A
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    B
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    D
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