Home
Class 10
MATHS
A golf ball has diameter equal to 4.1 cm...

A golf ball has diameter equal to 4.1 cm. Its surface has 150 dimples each of radius 2mm. Calculate total surface which is exposed to the surroundings. (Assume that the dimples are all hemispherical) `" "[pi=22//7]`

Text Solution

Verified by Experts

The correct Answer is:
`71.68 cm^(2)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MENSURATION

    VGS PUBLICATION-BRILLIANT|Exercise TRY THIS|12 Videos

  • MENSURATION

    VGS PUBLICATION-BRILLIANT|Exercise THINK & DISCUSS|2 Videos

  • MENSURATION

    VGS PUBLICATION-BRILLIANT|Exercise EXERCISE 10.4|16 Videos

  • COORDINATE GEOMETRY (MULTIPLE CHOICE QUESTION)

    VGS PUBLICATION-BRILLIANT|Exercise COORDINATE GEOMETRY(MULTIPLE CHOICE QUESTION)|30 Videos

  • PAIR OF LINEAR EQUATIONS IN TWO VARIABLES

    VGS PUBLICATION-BRILLIANT|Exercise EXERCISE|262 Videos

Similar Questions

Explore conceptually related problems

Find the volume and the total surface area of a hemisphere of radius 7.5 cm. (pi=22/7)

Find the volume and the total surface area of a hemisphere of radius 3.5 cm. (pi=22/7)

Knowledge Check

  • When liquid medicine of density p is to be put in the eye, it is done with the help of dropper. As the bulb on the top of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop. We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy. To determine the size, we calculate the net vertical force due to the surface tension T when the radius of the drop is R. When the force becomes smaller than the weight of the drop, the drop gets detached form the dropper. If r = 5 xx 10^(-4) m, rho = 10^3 kgm^(-3) , g = 10m//s^2 , T = 0.11 Nm^(-1) , the radius of the drop when it detaches from the dropper is approximately

    A
    `1.4 xx 10^(-3) m`
    B
    `3.3 xx 10^(-3) m`
    C
    `2.0 xx 10^(-3) m`
    D
    `4.1 xx 10^(-3) m`

    • Similar Questions

    Explore conceptually related problems

    Find the volume and surface area of a sphere of radius 2.1 cm. (pi=22/7)

    1000 drops of a liquid each of diameter 4 mm coalesce to form a single large drop. If surface tension of liquid is 35 dyne cm^(-1) . Calculate the energy evolved by the system in the process.

    The lower end of capillary tube of diameter 2.00 mm is dipped 8.00 cm below the surface of water in a beaker. What is the pressure required in the tube in order to blow a hemispherical bubble at its end in water ? The surface tension of water at temperature of the experiments is 7.30xx10^(-2)Nm^(1) . 1 atmospheric pressure =1.01xx10^(5) Pa, density of water =1000 "kg"//"m"^(3) , g=9.8xxms^(-2) . Also calculate the excess pressure .

    The lower end of a capillary tube of diameter 2.00 mm is dipped 8.00 cm below the surface of water in a beaker. What is the pressure required in the tube in order to blow a hemispherical bubble at its end in water? The surface tension of water at temperature of the experiment is 7.30xx10^(-2)Nm^(-1) . 1 atmospheric pressure = 1.01xx10^(5)Pa , density of water = 1000kgm^(-3),g=9.80ms^(-2) . Also calculate the excess pressure.

    The lower end of a capillary tube of diameter 2.00mm is dipped 8.00cm below the surface of water in a beaker. What is the pressure required in the tube in order to blow a hemispherical bubble at its end in water? The surface tension of water at temperature of the experiments is 7.30 times 10^2 Nm^-1 .1 atmospheric pressure =1.01 times 10^5 Pa density of water =1000 kg//m^3,g=9.80 ms^-2 . Also calculate the excess pressure.

    A cylindrical pillar has a diameter of 56 cm and is of 35 m high. There are 16 pillars around the building. Find the cost of painting the curved surface area of all the pillars at the rate of ₹5.50 per 1 m^2

    The lower end of a capillary tube of diameter 2.00 mm is dipped 8.00 cm below the surface of water in a beaker. What is the pressure required in the tube in order to blow a hemispherical bubble at its end in water. [The surface tension of waterat temperature of the experiment is 7.30xx10^(-2)Nm^(-1) . 1 atmospheric pressure = 1.01xx10^(5) Pa, density of water = 1000 kg m^(-3),g=9.80ms^(-2) ].

    Home
    Profile