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Find the perpendicular distance of that ...

Find the perpendicular distance of that point (3,-4) from the line `2x-5y+2=0`.

A

`28/sqrt29`units

B

`sqrt29 units`

C

28 units

D

None

Text Solution

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The correct Answer is:
A
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Find the perpendicular distance from the point (3,4) to the straight line :3x-4y+10=0

Find the perpendicular distance from the point (3,4) to the straight line: 3x-4y+10=0 .

Knowledge Check

  • The perpendicular distance of the point (2,4,-1) from line (x +5)/(1) =(y+3)/(4) = (z-6)/(-9) is

    A
    3
    B
    5
    C
    7
    D
    9
  • The perpendicular distance from the point (-2,3, 1) to the plane 2x – 3y – 6z + 5 = 0 is

    A
    ` sqrt14`
    B
    `1 sqrt14`
    C
    `5 sqrt14`
    D
    ` 2`
  • The foot of the perpendicular from the point (3, 4) on the line 3x-4y+5=0 is

    A
    `((81)/(25), (92)/(25))`
    B
    `((92)/(25), (81)/(25))`
    C
    `((46)/(25), (54)/(25))`
    D
    `((-81)/(25), (92)/(25))`
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    Find the distance of the point (3, - 5) from the line 3x - 4y - 26 = 0 .

    Find the perpendicular distances from the origin to the line x-3y-4=0 .

    Find the perpendicular distance from (-2,-3) to the line 5x-2y+4=0 .

    Find the length of the perpendicular drawn from the point (3, 4) to the straight line 3x - 4y + 10 = 0.