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The slope of a line perpendicular to the...

The slope of a line perpendicular to the line whose equation is `(x)/(3)-(y)/(4)=1` is

A

`-3`

B

`-(4)/(3)`

C

`-(3)/(4)`

D

`(1)/(4)`

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The correct Answer is:
To find the slope of a line perpendicular to the line given by the equation \(\frac{x}{3} - \frac{y}{4} = 1\), we will follow these steps: ### Step 1: Rewrite the equation in slope-intercept form We start with the equation: \[ \frac{x}{3} - \frac{y}{4} = 1 \] To convert this into the slope-intercept form \(y = mx + c\), we first isolate \(y\). ### Step 2: Isolate \(y\) We can rearrange the equation: \[ -\frac{y}{4} = 1 - \frac{x}{3} \] Multiplying through by -1 gives: \[ \frac{y}{4} = -1 + \frac{x}{3} \] Now, multiply both sides by 4 to eliminate the fraction: \[ y = 4\left(-1 + \frac{x}{3}\right) \] Distributing the 4: \[ y = -4 + \frac{4x}{3} \] ### Step 3: Identify the slope Now, we can express the equation in the slope-intercept form: \[ y = \frac{4}{3}x - 4 \] From this, we can see that the slope \(m\) of the line is: \[ m = \frac{4}{3} \] ### Step 4: Find the slope of the perpendicular line For two lines to be perpendicular, the product of their slopes must equal -1. If \(m_1\) is the slope of the original line and \(m_2\) is the slope of the perpendicular line, we have: \[ m_1 \cdot m_2 = -1 \] Substituting \(m_1 = \frac{4}{3}\): \[ \frac{4}{3} \cdot m_2 = -1 \] To find \(m_2\), we solve for it: \[ m_2 = -\frac{3}{4} \] ### Final Answer The slope of the line perpendicular to the given line is: \[ \boxed{-\frac{3}{4}} \]

To find the slope of a line perpendicular to the line given by the equation \(\frac{x}{3} - \frac{y}{4} = 1\), we will follow these steps: ### Step 1: Rewrite the equation in slope-intercept form We start with the equation: \[ \frac{x}{3} - \frac{y}{4} = 1 \] To convert this into the slope-intercept form \(y = mx + c\), we first isolate \(y\). ...
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