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On electrolysis in which of the followin...

On electrolysis in which of the following, `O_(2)` would be liberated at the anode?

A

Dilute `H_(2)SO_(4)` with Pt electrodes

B

Aqueous `AgNO_(3)` solution with Pt electrodes

C

Dilute `H_(2)SO_(4)` with Cu electrodes

D

Aqueous NaOH with a Fe cathode and a Pt anode

Text Solution

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The correct Answer is:
A, B, D
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(a) Write the cell reaction and calculate the emf of the following cell at 298 K : Sn (s) | Sn^(2+) (0.004 M) | | H^(+) (0.020 M) | H^2 (g) (1 bar) | Pt (s) [Given : E_(Sn^(2+)//Sn)^(@) = - 0.14 V ] (b) Give reasons : (i) On the basis of E° values, O_(2) gas should be liberated at anode but it is Cl_(2) gas which is liberated in the electrolysis of aqueous NaCl. (ii) Conductivity of CH_3COOH decreases on dilution.

Knowledge Check

  • Which of the following on electrolysis would, not evolve oxygen at the anode ?

    A
    Dilute `H_(2)SO_(4)` with Pt electrodes
    B
    Aqueous silver nitrate using Pt electrodes
    C
    Aqueous `Na_(2)SO_(4)` with Pt electrodes
    D
    50 % `H_(2)SO_(4)` with Pt electrodes

  • Which of the following does not liberate O_2 on heating?

    A
    `MgO`
    B
    `NaNO_3`
    C
    `Pb_3O_4`
    D
    `KClO_3`

  • When electrolysis is carried out on water, __________ gas is liberated at the anode.

    A
    Hydrogen
    B
    Oxygen
    C
    Nitrogen
    D
    Ozone

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    In the electrolysis of H_(2)O , 11.2 litres of H_(2) was liberated at cathode at NTP. How much O_(2) will be liberated at anode under the same conditions ?

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