Home
Class 11
MATHS
y =( 5)/(x^(2))+ ( 6)/(x) +2...

` y =( 5)/(x^(2))+ ( 6)/(x) +2`

Text Solution

Verified by Experts

The correct Answer is:
` ( -10 )/( x^(3) )- ( 6)/( x^(2))`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • LIMITSAND DERIVATIVES

    SUBHASH PUBLICATION|Exercise THREE MARKS QUESTIONS WITH ANSWERS|7 Videos

  • LIMITSAND DERIVATIVES

    SUBHASH PUBLICATION|Exercise FIVE MARKS QUESTIONS WITH ANSWERS|1 Videos

  • INTRODUCTION TO THREE DIMESIONAL GEOMETRY

    SUBHASH PUBLICATION|Exercise 2/3 MARKS QUESTIONS WITH ANSWERS|10 Videos

  • LINEAR INEQUALITY

    SUBHASH PUBLICATION|Exercise Three Marks Questions With Answer|13 Videos

Similar Questions

Explore conceptually related problems

Solve the system of equations (2)/( x) + ( 3)/( y) +(10 )/( z) = 4 (4)/( x) -(6)/( y) +(5)/(z) =1 (6)/(x) +(9)/( y) -(20 )/( z) = 2

If y=f((3x+4)/(5x+6))andf'(x)=tanx^(2), then (dy)/(dx) is equal to

Knowledge Check

  • If x,y,z in R , then the value of determinant |((5^(x)+5^(-x))^(2) , (5^(x)-5^(-x))^(2),1),((6^(x)+6^(-x))^(2),(6^(x)-6^(-x))^(2), 1),((7^(x)+7^(-x))^(2),(7^(x)-7^(-x))^(2),1)| is

    A
    10
    B
    12
    C
    1
    D
    0

  • The two circles x^(2) + y^(2) - 2x + 22y + 5 = 0 and x^(2) + y^(2) + 14x + 6y + k = 0 intersect orthogonally provided k is equal to...

    A
    47
    B
    `-47`
    C
    49
    D
    `-49`

  • Area of the parallelogram formed by 2 x^(2)+5 x y+3 y^(2)=0 and 2 x^(2)+5 x y+3 y^(2)+3 x+4 y+1=0 is

    A
    2
    B
    1
    C
    4
    D
    3

    • Similar Questions

    Explore conceptually related problems

    Solve for x and y 5/(x-1)+1/(y-2)=2" and "6/(x-1)-3/(y-2)=1

    Solve for x and y : (6)/(x-1)-(3)/(y-2)=1 (5)/(x-1)-(1)/(y-2)=2 , where x ne 1, y ne 2 .

    Find the degree of each of the polynomials given below (i) x ^(5) - x ^(4) +3 (ii) x ^(2) + x -5 (iii) 5 (iv) 3x ^(6) + 6y ^(3) -7 (v) 4- y ^(2) (vi) 5t - sqrt3

    The two circles x^(2) + y^(2) -2x + 6y + 6 = 0 and x^(2) + y^(2) -5x + 6y + 15 = 0

    The number of common tangents to the circles x^(2) + y^(2) = 4 and x^(2) +y^(2) - 6x - 8y -24 =0 is,

    Home
    Profile