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Prove geometrically lim ( theta to 0) (...

Prove geometrically ` lim _( theta to 0) ( tan theta ) /( theta ) =1 ` is in radians

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lim _( theta to 0) ( sin 5theta)/( tan 4theta)

Prove geometrically lim_(x to 0) (sintheta)/(theta)=1 (theta is measured in radians).

Knowledge Check

  • lim_(theta rarr pi/2) (pi/2- theta)/(cot theta) =

    A
    0
    B
    (-1)
    C
    1
    D
    `oo`

  • lim_(theta rarr 0)(tan theta - sin theta)/(theta^(3))=

    A
    0
    B
    2
    C
    (1/2)
    D
    (1/3)

  • lim_(theta rarr 0) (1-cos theta)/(theta. costheta)=

    A
    1/2
    B
    `sqrt2`
    C
    0
    D
    2

    • Similar Questions

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    Prove that lim_(thetararr0)(sin theta)/(theta)=1 .

    lim _( theta to x //2) ( cos theta )/( ( pi //2-theta))

    lim_(theta rarr 0) (1-cos theta)/(theta sin theta) =

    lim_(theta rarr 0)(sin 5 theta - sin 3 theta)/(theta)=

    The value of lim_(theta to 0)(1-cos 4theta)/(1-cos 6 theta) is

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