An object of mass 0.5 kg, moving in a circular path of radius 0.25m, experiences a centripetal acceleration of constant magnitude 9 `m//s^(2)`. What is the object's angular speed?

Options

A. `2.3rad//s`
B. 4.5rad/s
C. 6rad/s
D. 12rad/s

Answer

C

Explanation

By combining the equation for centripetal acceleration `a_(c)=v^(2)//r`, with `v=romega,` we find
`a_(c)=(v^(2))/(r)=((romega)^(2))/(r)=omega^(2)r implies omega=sqrt((a_(c))/(r))=sqrt((9m//s^(2))/(0.25m))=6s^(-1)`