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A certain charge Q is divided into two p...

A certain charge Q is divided into two parts q and `Q-q`, wheich are then separated by a cetain distance. What must q be in terms of Q to maximum the electrostatic repulsion between the two charges?

Text Solution

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The correct Answer is:
q=Q/2
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Knowledge Check

  • A certain charge Q is divided at first into two parts, q and Q-q. later on the charges are placed at a certain distance. If he force of interaction between two charges is maximum, then

    A
    `Q/q=4/1`
    B
    `Q/q=2/1`
    C
    `Q/q=3/1`
    D
    `Q/q=1/3`

  • Charge Q is divided into two parts which are then kept some distance apart . The force between them will be maximum if the two parts are

    A
    `(Q)/(2)` and `(Q)/(2)`
    B
    `(Q)/(2)` and `(3Q)/(4)`
    C
    `(Q)/(2)` and `(2Q)/(3)`
    D
    `e` and `(Q - e)`

  • Two point charges Q and - Q //4 are separated by a distance X . Then .

    A
    potential is zero at a point on the axis which is ` x//3` on the right side of the cahrge `-q//4`
    B
    potential is zero at a point on the axis which is `x//5` on the left side fo the charge `- Q//4`
    C
    electric field is zero at a point on the axis which is at a distance `x` on the right side fo the charge `- Q//4`
    D
    there exist two points on the axis where electric field is zero.

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