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Half of the core of a solenoid of 2xx...

Half of the core of a solenoid of `2xx 10^(-3) m^(2)` cross -section , is made up of air and the other half iron `(mu_(r)=500)`. The length of the solenoid is 2 m . If the number of turns is 1000, calculate its coefficient of self induction .

Text Solution

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The correct Answer is:
0.315 H
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A solenoid has a core of a material with relative permeability 400. The windings of the solenoid are insulated from the core and carry a current of 2A. If the number of turns is 1000 permetre, calculate (a) H

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Knowledge Check

  • A solenoid having a core of cross-section 4cm^(2) , half air and half iron (relative permeability =500), is 22 cm long . If the number of turns on it is 10^(3) its self inductance is __

    A
    570 H
    B
    57 H
    C
    5.7 H
    D
    0.57 H
  • The inductance of a solenoid 0.5m long of cross-sectional area 20cm^(2) and with 500 turns is

    A
    `12.5 mH`
    B
    `1.25mH`
    C
    `15.0mH`
    D
    `0.12mH`
  • A solenoid of length 0.5 m has a radius of 1 cm and is made up of 500 turns. It carries a current of 5 A. The magnetic field inside the solenoid is

    A
    `3.14 xx 10^(-3) T`
    B
    `6.28 xx 10^(-3) T`
    C
    `9.14 xx 10^(-3) T`
    D
    `1.68 xx 10^(-3) T`
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    Calculate the self-inductance of an air-cored solenoid 50 cm long and 2 cm radius if the number of turns in the coil of solenoid is 400.

    A solenoid has a core of a material with relative permeability 400. The windings of the solenoid are insulated from the core and carry a current of 2A. If the number of turns is 1000 permetre, calculate (d) the magnetising current i_(m)

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