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STATEMENT-1: Gram molecular mass of O(2)...

STATEMENT-1: Gram molecular mass of `O_(2)` is 32.
STATEMENT-2: Relative atomic mass of oxygen is 32 a.m.u.

A

If both the statement are TRUE and STATEMENT -2 is the correct explanation of STATEMENT-1

B

If both the statement are TRUE but STATEMENT-2 is NOT the correct explanation of STATEMENT-1

C

If STATEMENT- is 1 TRUE and STATEMENT-2 is FALSE

D

If STATEMENT-1 is FALSE and STATEMENT-2 is TRUE

Text Solution

Verified by Experts

The correct Answer is:
C
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What is meant by saying that 'the molecular mass of oxygen is 32 '?

Knowledge Check

  • Assertion : The molecular weight of oxygen is 32 amu. Reason : The atomic weight of oxygen is 16 amu

    A
    If both Assertion & Reason are true and the reason is the correct explanation of the assertion.
    B
    If both Assertion & Reason are true but the reason is not the correct explanation of the assertion.
    C
    If Assertion is true statement but Reason is false.
    D
    If both Assertion and Reason are false statements.

  • STATEMENT-1: when 2 faraday of charge is passed through 0.1 M H_2SO_4 (aq) ,11.2 litre O_2 evolved at STP. STATEMENT-2: Molecular mass of oxygen is 32

    A
    If both the statements are TRUE and STATEMENTS-2 is the correct explantion of STATEMENTS-1
    B
    If both the statements are TRUE but STATEMENTS-2 is NOT the correct explanation of STATEMENTS-2
    C
    If STATEMENTS-1 is TRUE and STATEMENTS-2 is FALSE
    D
    If STATEMENT-1 is FALSE and STATEMENT-2 is TRUE

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    What is rms velocity of O_(2) gas at 127^(@)C. ? The molecular weght of oxygen is 32.

    The distance between the carbon atom and the oxygen atom in a carbon monoxide molecule is 1.1 Å . Given, mass of carbon atom is 12 a.m.u. and mass of oxygen atom is 16 a.m.u., calculate the position of the centre of mass of the carbon monoxide molecule

    (a) Define gram molecular mass of a substance. How much is the gram molecular mass of oxygen ? (b) If sulphur exists as S_(8) molecules, calculate the number of moles in 100 g of sulphur. (S = 32 u)

    Mole conept: Calculate the follwing in 48g of oxygen gas (diaxygen) at room temperature (25^(@) C) : (i) moles of O_(2) , (Ii) number of O_(2) molecules, (iii) number of O atoms, and (iv) number of electrons. Strategy: The molecular mass of dioxygen (O_(2)) is 32 mu Thus, its molar mass is 32.0g mol^(-1) , Now, use the needed information: (a) one mole of O_(2) contains Avogadro's number of O_(2) molecules, (b) one O_(2) molecules contains 2 oxygen atons, and (c) one oxygen atom contains 8 electrons.

    Calculate the mass of the following: (i) 0.5moles of O_(2) gas (ii) 0.5moles of O atoms (iii) 3.011xx10^(23)"atoms of O" (iv) 6.022xx10^(23)"molecules of "O_(2) (Givem: Gram atomic mass of oxygen=16g) Gram of molecular mass of oxygen (O_(2)) =32g)

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