Text Solution

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The correct Answer is:
`ArarrQ; BrarrP; CrarrR; DrarrS`

`eta=(T_(2)-T_(1))/(T_(2))=(|-w_("Total")|)/(q_(2))implies (500-350)/(500)=(|-w_("Total")|)/(10)`
Work done in one cycle = 3
Work done in two cycles = 3 `xx` 2 = 6
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