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On dissolving 2.0 g of metal in sulphuri...

On dissolving 2.0 g of metal in sulphuric acid ,4.51 g of the metal sulphate was formed . The specific heat of the metal is 0.057 cal `g^(-1).^(@)C^(-1)`. What is the valency of metal ?

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On dissolving 2.0g of metal in sulphuric acid. 4.51g of the metal sulphate was formed. The specific heat of the metal is 0.057 cal g^(-1) . What is the valency of the metal and exact atomic mass?

On dissolving 2.0 g of a metal in sulphuric acid, 4.51 grams of the metal sulphate was formed. The specific heat of the metal is 0.057 cal/g. What is the valency of the metal and its exact atomic weight?

Knowledge Check

  • Upon fully dissolving 2.0 g of a metal in sulfuric acid, 6.8 g of the metal sulfate is formed. The equivalent weigth of the metal is-

    A
    `13.6 g`
    B
    `20.0g`
    C
    `4.0g`
    D
    `10.0g`

  • 0.5 g of metal nitrate gave 0.43 g of metal sulphate

    A
    The equivalent wt. of the metal is `0.38`
    B
    The atomic weight of the metal is 76
    C
    The atomic wt. of metal is `38 x ` (x = valency of metal )
    D
    The atomic weight of metal is 19

  • A solution of a salt of a metal was electrolysed for 150 minutes by passing 0.15 A current. The weight of the metal deposited was 0.783 g. The specific heat of the metal is 0.057" cal"//gK . The atomic mass X of the metal is :

    A
    `111.80" g"//mol`
    B
    `52.2" g"//mol`
    C
    `200" g"//mol`
    D
    `250" g"//mol`

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    2 g of a metal in H_(2) SO_(4) gives 4.51 g of the metal sulphate. The specific heat of metal is 0.057 cal g^(-1) . Calculate the valency and atomic weight of metal.

    Specific heat of water is 1"cal"//g//^(@)C .

    1.0 g of metal nitrate gave 0.86 g of metal sulphate. Calculate the equivalent weight of metal.

    The specific heat of a metal is 0.836 J//g . The approximate at.wt.is:

    The specific heat of a bivalent metal is 0.16. the approximate equivalent mass of the metal will be:

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