The correct expression derived for the energy of an electron in the `n^(th)` energy level is for H-atom :

Options

A. `E_(n)=(2pi^(2)me^(4)K^(2))/(n^(2)h^(2))`
B. `E_(n)=(pi^(2)me^(4)K^(2))/(2n^(2)h^(2))`
C. `E_(n)=(2pi^(2)me^(2)K^(2))/(n^(2)h^(2))`
D. `E_(n)= -(2pi^(2)me^(4)K^(2))/(n^(2)h^(2))`

Answer

D