Calculate `Delta_(r)G` for the reaction at `27^(@)C` `H_(2)(g)+2Ag^(+)(aq)hArr2Ag(s)+2H^(+)(aq)` Given : `P_(H2)=0.5` bar, `[Ag^(+)]=10^(-5)M,` `[H^(+)]=10^(-3)M,Delta_(r)G^(@)[Ag^(+)(aq)]=77.1kJ//mol`
A
`-154.2kJ//mol`
B
`-178.9kJ//mol`
C
`-129.5kJ//mol`
D
None of these
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The correct Answer is:
C
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Calculate Delta_(r)G for the reaction at 27^(@)C H_(2)(g) + 2Ag^(+)(aq) implies 2Ag(s) + 2H^(+)(aq) Given : P_(H_2) = 0.5 , [Ag^+] = 10^(-5)M , [H^+] = 10^(-3) M , Delta_(f) G^(@) [Ag^(+)(aq)] = 77.1 kJ//mol
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Knowledge Check
The reaction Ag ^(2+)(aq) + Ag (s) hArr 2 Ag ^(+) (aq) An example of.
A
Reduction
B
Oxidation
C
Disproportionation
D
none
The cell reaction 2 Ag^+ (aq) + H_2(g) to 2H^+ (aq) + 2 Ag(s) is best represented by :
A
`Ag(s)|Ag^+ (aq)||H^+ (aq)|H_2(g)| Pt(s)`
B
`Pt(s)|H_2(g) |H^(+)(aq)||Ag^(+)(aq)Ag(s)`
C
`Ag(s) |Ag^(+)(aq)||H_2(g)|H^(+)(aq)|Pt(s)`
D
`Ag^(+)(aq)|Ag(s)||H_2(g)|H^(+)(aq)`
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