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An excited state of H atom emits a photo...

An excited state of H atom emits a photon of wavelength `lamda` and returns in the ground state. The principal quantum number of excited state is given by:

A

`sqrt(lamdaR(lamdaR-1))`

B

`sqrt((lamdaR)/((lamdaR-1))`

C

`sqrt(lamdaR(lamdaR-1)`

D

`sqrt((lamdaR-1)/((lamdaR))`

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Knowledge Check

  • An excited hydrogen atom emits a photon of wavelength lambda in returning to the ground state. If R is the Rydberg constant, then the quantum number n of the excited state is

    A
    `sqrt(lambda R)`
    B
    `sqrt(lambda R-1)`
    C
    `sqrt(lambda (lambdaR-1))`
    D
    `sqrt((lambda R)/(lambdaR-1))`

  • Hydrogen atom from excited state comes to the ground state by emitting a photon of wavelength lambda . If R is the Rydberg constant, then the principal quatum number n of the excited state is

    A
    `sqrt((lambdaR)/(lambdaR-1))`
    B
    `sqrt((lambda)/(lambdaR-1))`
    C
    `sqrt((lambdaR^2)/(lambdaR-1))`
    D
    `sqrt((lambdaR)/(lambda-1))`

  • A hydrogen atom ia in excited state of principal quantum number n . It emits a photon of wavelength lambda when it returnesto the ground state. The value of n is

    A
    `sqrt(lambda R (lambda R - 1))`
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    `sqrt((lambda (R - 1))/(lambda R))`
    C
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    D
    `sqrt lambda (R - 1)`

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