Home
Class 11
CHEMISTRY
An equilibrium mixture at 700 K of 0.05M...

An equilibrium mixture at 700 K of 0.05M `N_(2)(g) and 0.2 M NH_(3)(g)` is present in a container .Now if this equilibrium is disturbed by adding `N_(@)` (g) so that its concentration becomes 0.15M just after addition then which of the following graph represents the above situation more appropriately:

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
a
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM

    NARENDRA AWASTHI|Exercise Level 2|1 Videos
  • CHEMICAL EQUILIBRIUM

    NARENDRA AWASTHI|Exercise Level 2|1 Videos
  • ATOMIC STUCTURE

    NARENDRA AWASTHI|Exercise Exercise|273 Videos
  • DILUTE SOLUTION

    NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos

Similar Questions

Explore conceptually related problems

Given the following reaction at equilibrium N_(2)(g) + 3H_(2)(g)hArr2NH_(3)(g) . Some inert gas at constant pressure is added to the system. Predict which of the following facts:

For the equilibrium N_(2)(g)+3H_(2)(g) Leftrightarrow 2NH_(3)(g)" at "1000^(0)C the equilibrium constant is very low, then which of the following is correct at equilibrium ?

For the reaction H_(2)(g) + I_(2)(g)hArr2HI(g) at 721 K the value of equilibrium constant (K_(c)) is 50. When the equilibrium concentration of both is 0.5 M, the value of K_(p) under the same condtions will be

Increased pressure shifts the equilibrium of the reaction: N_(2)(g)+3H_(2)(g)harr2NH_(3)(g) so as to

4g H_(2) & 127g I_(2) are mixed "&" heated in "10" lit closed vessels until equilibrium is reached. If the equilibrium concentration of HI is 0.05M total number of moles present at equilibrium is

0.6 mole of NH_(3) in a reaction vessel of 2dm^(3) capacity was brought to equilibrium. The vessel was then found to contain 0.15 mole of H_(2) formed by the reaction 2NH_(3)(g) hArr N_(2)(g)+3H_(2)(g) . Which of the following statements is true?