Home
Class 12
CHEMISTRY
Figure explains elevation in boiling poi...

Figure explains elevation in boiling point when a non-volatile solute is added to a solvent. Variation of vapour pressure with temperaure and elevation in boiling point is marked.

Given that `DeltaT_(b)` is the elevation in boiling point of the solvent in a solution of molarity m then `lim_(m rarr 0) ((Delta T_(b))/(m))` is equal to:

A

`K_(b)` (molal elevation constant)

B

`L_(v)` (latent heat of vaporisation)

C

`DeltaS` (entropy change)

D

x (mole fraction of solute)

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • GRAPHICAL INTERPRETATION

    GRB PUBLICATION|Exercise Comprehension 26|1 Videos

  • GRAPHICAL INTERPRETATION

    GRB PUBLICATION|Exercise Comprehension 27|1 Videos

  • GRAPHICAL INTERPRETATION

    GRB PUBLICATION|Exercise Comprehension 24|1 Videos

  • F-BLOCK ELEMENTS

    GRB PUBLICATION|Exercise Subjective type|7 Videos

  • HYDROCARBON (ALIPHATIC)

    GRB PUBLICATION|Exercise Previous years jee questions|28 Videos

Similar Questions

Explore conceptually related problems

Figure explains elevation in boiling point when a non-volatile solute is added to a solvent. Variation of vapour pressure with temperaure and elevation in boiling point is marked. Elevation in b.p of an aqueous urea solution is 0.52^(@) (K_(b) = 0.52^(@) mol^(-1)kg) . Hence, mole fraction of urea in this solution is:

Figure explains elevation in boiling point when a non-volatile solute is added to a solvent. Variation of vapour pressure with temperaure and elevation in boiling point is marked. Ratio of DeltaT_(b)//K_(b) of 6% AB_(2) and 9% A_(2)B (AB_(2) and A_(2)B both are non-electrolytes) is 1 mol/kg in both cases. Hence, atomic masses of A and B are respectively.

Given that DeltaT_(f) is the depression in freezing point of the solvent in a solution of a non-volatile solute of molarity m ,the quantity underset(m rarr0)(Lt) (DeltaT_(f)//m) is equal to ……………. .